Question

Solve this................

Answer 1

hope its clear...........

Answer 2

HEY Buddy.....!! here is ur answer

We have to prove that....cosA+sinA = √2cosA

Given that : cosA–sinA = √2sinA.....(1)

=> cosA = √2sinA+sinA

=> cosA = sinA(√2+1)

=> sinA/cosA = 1/(√2+1)

=> tanA = 1/(√2+1) × (√2–1)/√2–1)

=> tanA = (√2–1)/(√2)²–(1)²

=> tanA = (√2–1)/1

=> sinA/cosA = √2–1

=> sinA = √2cosA–cosA

=> sinA+cosA = √2cosA

=> cosA+sinA = √2cosA

HENCE PROVED

I hope it will be helpful for you....!!

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