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hope its clear...........
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HEY Buddy.....!! here is ur answer
We have to prove that....cosA+sinA = √2cosA
Given that : cosA–sinA = √2sinA.....(1)
=> cosA = √2sinA+sinA
=> cosA = sinA(√2+1)
=> sinA/cosA = 1/(√2+1)
=> tanA = 1/(√2+1) × (√2–1)/√2–1)
=> tanA = (√2–1)/(√2)²–(1)²
=> tanA = (√2–1)/1
=> sinA/cosA = √2–1
=> sinA = √2cosA–cosA
=> sinA+cosA = √2cosA
=> cosA+sinA = √2cosA
HENCE PROVED
I hope it will be helpful for you....!!
THANK YOU ✌️✌️
MARK IT AS BRAINLIEST
We have to prove that....cosA+sinA = √2cosA
Given that : cosA–sinA = √2sinA.....(1)
=> cosA = √2sinA+sinA
=> cosA = sinA(√2+1)
=> sinA/cosA = 1/(√2+1)
=> tanA = 1/(√2+1) × (√2–1)/√2–1)
=> tanA = (√2–1)/(√2)²–(1)²
=> tanA = (√2–1)/1
=> sinA/cosA = √2–1
=> sinA = √2cosA–cosA
=> sinA+cosA = √2cosA
=> cosA+sinA = √2cosA
HENCE PROVED
I hope it will be helpful for you....!!
THANK YOU ✌️✌️
MARK IT AS BRAINLIEST
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