Question

Solve this And please confirm my answer i.e. 5%.​

Answer 1

Given formula :-

$\sf{z\: =\: {\dfrac{a^2b}{c^{1/2}}}}$

It can also be written as :-

$\sf{z\: =\: a^2bc^{-1/2}}$

The maximum percentage error in z will be

$\implies\:\bigg({\dfrac{\triangle\:z}{z}}\bigg)\: \times\: 100\: =\: 2\: \times\: \bigg({\dfrac{\triangle\:a}{a}}\: \times\: 100\:\bigg)\: +\: \bigg({\dfrac{\triangle\:b}{b}}\: \times\: 100\:\bigg)\: +\: {\dfrac{1}{2}}\: \times\: \bigg({\dfrac{\triangle\:c}{c}}\: \times\: 100\:\bigg)$

⟹ z = 2 × 2 + 3 + 2

= 4 + 3 + 2

= 9 %

Therefore, maximum percentage error will be 9%