solve this and show how #vectors class 12
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Q. A vector makes an angle of 90°, 105°,45° with positive directions of X, Y, Z axis. Find direction ratios
Sol. Direction ratios comes from the more basic idea of direction cosines.
=>Direction cosines are the cosines of angles made by a vector with coordinate axes.
=>So, Here direction cosines are
![l = \cos90 = 0 \\ m = \cos135 = \frac{ - 1}{ \sqrt{2} } \\ n = \cos45 = \frac{1}{ \sqrt{2} } l = \cos90 = 0 \\ m = \cos135 = \frac{ - 1}{ \sqrt{2} } \\ n = \cos45 = \frac{1}{ \sqrt{2} }](https://tex.z-dn.net/?f=l+%3D++%5Ccos90+%3D+0+%5C%5C+m+%3D++%5Ccos135++%3D++%5Cfrac%7B+-+1%7D%7B+%5Csqrt%7B2%7D+%7D++%5C%5C+n+%3D++%5Ccos45+%3D++%5Cfrac%7B1%7D%7B+%5Csqrt%7B2%7D+%7D+)
Here, l, m, n are direction cosines
=>When any constant is multiplied with the direction cosines, they are called direction ratios.
So, λl, λm, λn,are direction ratios where λ=constant
![answer = > lamda(0) \: lamda( \frac{ - 1}{ \sqrt{2} } ) \: lamda( \frac{1}{ \sqrt{2} } ) answer = > lamda(0) \: lamda( \frac{ - 1}{ \sqrt{2} } ) \: lamda( \frac{1}{ \sqrt{2} } )](https://tex.z-dn.net/?f=answer+%3D++%26gt%3B+lamda%280%29+%5C%3A+lamda%28+%5Cfrac%7B+-+1%7D%7B+%5Csqrt%7B2%7D+%7D+%29+%5C%3A+lamda%28+%5Cfrac%7B1%7D%7B+%5Csqrt%7B2%7D+%7D+%29)
=>Direction ratios help in Simplifying calculations.
For example, if we take x= root 2, then direction ratios becomes 0,-1, 1.
Hence, calculation becomes easier with these.
Sol. Direction ratios comes from the more basic idea of direction cosines.
=>Direction cosines are the cosines of angles made by a vector with coordinate axes.
=>So, Here direction cosines are
Here, l, m, n are direction cosines
=>When any constant is multiplied with the direction cosines, they are called direction ratios.
So, λl, λm, λn,are direction ratios where λ=constant
=>Direction ratios help in Simplifying calculations.
For example, if we take x= root 2, then direction ratios becomes 0,-1, 1.
Hence, calculation becomes easier with these.
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