solve this and tell me by which theorem u solved ..if possible state that!! plzzz
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Anonymous:
Alternate segment, theory will be use
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It's given that it's a rhombus, and sice /_QPT=60°,
We know that tangent is perpendicular to radius.
therefore,/_OPT=90°
/_OPT=/_OPQ+/_QPT
therefore, 90°=/_OPQ+60°
so, 30°=/_OPTQ.
Since ∆OPQ is isosceles, we have
/_OPQ=/_OQP
So /_OQP=30°
By angle sum property, we get
/_POQ=120°
therefore, x=120°------(opposite angles of Rhombus)
Hope this answer helps...thank you
We know that tangent is perpendicular to radius.
therefore,/_OPT=90°
/_OPT=/_OPQ+/_QPT
therefore, 90°=/_OPQ+60°
so, 30°=/_OPTQ.
Since ∆OPQ is isosceles, we have
/_OPQ=/_OQP
So /_OQP=30°
By angle sum property, we get
/_POQ=120°
therefore, x=120°------(opposite angles of Rhombus)
Hope this answer helps...thank you
Yeah, you are correct
agar aisa hai to bhai then I don't know..... delete my answer so you can get a relevant one
okk good
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2
Let me try, am solving on paper
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My pleasure
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