Question

solve this answer fast as soon as​

Answer 1

SEE THE AATACHMENT YOUR ANSWER IS THIS AND I THINK IT IS CORRECT

#TOGETHER WE GO FAR✔✔

Answer 2

Answer:

heya mate first we factorise the polynomial

${x }^{2} + 4x + 4$

${x}^{2} + 2x + 2x + 4$

$x(x + 2) + 2(x + 2)$

$(x + 2)(x + 2)$

$hence \: x = - 2$

putting value of x in

$log_{x + 2}$

$hence \: log_{ - 2 + 2} = log_{0}$

$anything \: log_{0} = 0$

therefore

$log_{0}( {x}^{2} + 4x + 4) = 0$

Explanation:

hope this helps you

*but I am not confirmed whether this is correct or not