solve this anyone.......
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1 is the correct answer.
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In triangle ABC right anglead at A
tan C = √3 = P/B
So P=√3 and B=1
Using Pythagoras Theorem
AC²= AB²+BC²
AC²= 1+3
AC=2
Sin B Cos C + Cos B Sin C.
P/H. B/H +B/H P/H
1/2 1/2 +√3/2+√3/2
1/4+3/4
4/4 = 1
So answer is 1.
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