Question

solve this as soon as possible......​

Answer 1

Answer(:a^2+b^2)/(a^2-b^2)

sin theta/cos theta =a/b

or, asin theta/bcos theta=a^2/b^2

or,(asin theta +b cos theta)/(asin theta-bcos theta)=(a^2+b^2)/(a^2-b^2)

this is the answer of your question

please make me the brainliest