The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another
bat and 2 more balls of the same kind for Rs 1300. Represent this situation with Elemination method
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Answer:
Let x be the cost of 1 bat
Let y be the cost of 1 ball
Cost of 3 bats = 3x
Cost of 6 balls = 6y
Cost of 3 balls = 3y
The coach of a cricket team buys 3 bats and 6 balls for ₹ 3900
3x+6y=3900
She buys another bat and 3 more balls of the same kind for ₹1300.
x+3y=1300
So, situation algebraically :
3x+6y=3900
x+3y=1300
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