Question

Solve this attachment ...... ⬆️⬆️⬆️⬆️⬆️⬆️​

Answer 1

Answer:

$\frac{ {3}^{40} + {3}^{39} }{ {3}^{41} - {3}^{40} } \\ \frac{( {3)}^{39}( 3 + 1)}{( {3)}^{39}(3 \times 3 + 3) } = \frac{4}{12} \\ \frac{1}{3}$

It's answer is 1/3 not 2/3

$\\ \\ \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty$

HOPE IT HELPS..........

Answer 2

Answer:

3^40+3^39/3^41-3^40

=3^39(3+1)/3^40(3-1)

=4/3x2=2/3

Step-by-step explanation:

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