Math, asked by dysm30530, 9 months ago

Solve this attachment ... ⬆️⬆️⬆️⬆️​

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Answered by BrainlyPopularman
1

Answer:

GIVEN THAT :-

 \frac{ {9}^{n}   \times {3}^{2}  \times  {( {3}^{ -  \frac{n}{2} } )}^{ - 2}  -  {(27)}^{n} }{ {3}^{3m}  \times  {2}^{3} }  =  \frac{1}{27}

=

 \frac{ {3}^{2n + 2}  \times  {3}^{n}  -  {3}^{3n} }{ {3}^{3m} }  =  \frac{8}{24}  \\  \\  =  >  \frac{ {3}^{3n + 2}  -  {3}^{3n} }{ {3}^{3m} }  =  \frac{8}{27}  \\  \\  =  >  \frac{ {3}^{3n(8)} }{ {3}^{3m} }  =  \frac{8}{27}  \\  \\  =  >  {3}^{3n - 3m}  =  {3}^{ - 3}  \\  \\  =  > 3n - 3m =  - 3 \\  \\  =  > m - n  = 1

HOPE YOU LIKE IT...

Answered by dheerajy30530
2

Answer is in the attachment ..

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