Question

solve this by substitution method......step by step plss
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Answer 1

Multiply root3 in eq. 1

and root2 in eq. 2

you will get

root6x+root9y=0---------1

root6x-root16y=0-------- 2

subtracting both eq.

(root9 + root16 )y =0

3y+4y=0

y=0

putting y in eq. 1

we will get x=0

so x and y both values are 0

Answer 2

Answer:

Multiply root3 in eq. 1

and root2 in eq. 2

you will get

root6x+root9y=0---------1

root6x-root16y=0-------- 2

subtracting both eq.

(root9 + root16 )y =0

3y+4y=0

y=0

putting y in eq. 1

we will get x=0

so x and y both values are 0

Step-by-step explanation: