solve this by substitution method......step by step plss
Attachments:
Answers
Answered by
4
Multiply root3 in eq. 1
and root2 in eq. 2
you will get
root6x+root9y=0---------1
root6x-root16y=0-------- 2
subtracting both eq.
(root9 + root16 )y =0
3y+4y=0
y=0
putting y in eq. 1
we will get x=0
so x and y both values are 0
vipin55:
sorry*
np
i m so sorry
kk np
you have to told me at that time yr
hope any other will give right one
i thought ki sayad sahi hoga but abhi notice kiya
ok
sorry once again
np
Answered by
1
Answer:
Multiply root3 in eq. 1
and root2 in eq. 2
you will get
root6x+root9y=0---------1
root6x-root16y=0-------- 2
subtracting both eq.
(root9 + root16 )y =0
3y+4y=0
y=0
putting y in eq. 1
we will get x=0
so x and y both values are 0
Step-by-step explanation:
Similar questions