Question

solve this eqn to get two roots from use of quadratic formula
${x}^{2} + 9x + 16$
​

Answer 1

Answer:

$x= \frac{ - 9 + \sqrt{17} }{2} \: \: \: \: \: \: \: \: \frac{ - 9 - \sqrt{17} }{2}$

Step-by-step explanation:

YOU QUESTION IS THAT

○FIND TWO ROOTS FROM THIS EQN BY USE OF QUADRATIC FORMULA

${x}^{2} + 9x + 16$

$d = {b}^{2} - 4ac \\ \: \: \: \: = {9}^{2} - 64 \\ \: \: \: \: = 81 - 64 \\ \: \: \: \: = 17 \\ x = \frac{ - b + - \sqrt{d} }{2a} \\ \: \: \: \: = \frac{ - 9 + \sqrt{17} }{2} \: \: \: \: \: \: \: \: \frac{ - 9 - \sqrt{17} }{2}$

Answer 2

${x}^{2} + 9x + 16$

$d = {b}^{2} - 4ac \\ \: \: \: \: = {9}^{2} - 64 \\ \: \: \: \: = 81 - 64 \\ \: \: \: \: = 17 \\ x = \frac{ - b + - \sqrt{d} }{2a} \\ \: \: \: \: = \frac{ - 9 + \sqrt{17} }{2} \: \: \: \: \: \: \: \: \frac{ - 9 - \sqrt{17} }{2}$