solve this equation
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6x2-30x+36=0
divide both sides by 6
x2-5x+6=0
by splitting middle term
x2-2x-3x+6=0
x(x-2)-3(x-2)
x-2)(x-3)
hence keep x-2=0
so x=2
andx-3=0
so x=3
hence x has two values,2and3 because it is a quadratic equation
hope this will help you and if so please mark it as brainliest
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