Question

solve this equation ,
2u+3(1/3)=2​

Answer 1

Step-by-step explanation:

ax2+bx+c=0⟹x=−b±b2−4ac√2a (for a≠0)[1]

Here a=1, b=k−1k and c=−1

Let’s start with the bit under the root:

b2−4ac=

(k−1k)2−4(1)(−1)=

k2−2+1k2+4=

k2+2+1k2=

k4+2k2+1k2=

(k2+1)2k2=

(k2+1k)2=

(k+1k)2

The root removes the square so we have two situations:

k+1k

and

−(k+1k)=−k−1k

And for the minus b

−(k−1k)=

1k−k

So we have either

2k or −2k on the numerator so we have

x=1k or x=−k (for k≠0)