Question

Solve this equation :-
2x square - 8 + 12
Only legend can understand

@Gadhe
single​

Answer 1

Answer:

$2{x}^{2} - 8x + 12$

Solving through Sri Dharacharya Method,

$x = \dfrac{ - b\pm \: \sqrt{ {b}^{2} - 4ac } }{2a}$

Here,

a = 2

b = -8

c = 12

$x = \dfrac{8\pm \sqrt{64 - 96} }{4} \\ \\ x = 2\pm \dfrac{ \sqrt{ - 32} }{4}\\ \\ x = 2\pm \dfrac{32i}{4} \\ \\ x = 2 + 8i \: \: or \: \: x = 2 - 8i$

Hope it helps

Answer 2

Kya bkwass h

Pehle hi Meri lagi padi h ಥ‿ಥ