Question

solve this equation 3a+5b=26 ; a+5b=22 ​

Answer 1

Step-by-step explanation:

$\: \: 3a + 5b = 26 \\ \: \: a \: \: + 5b = 22 \\ - \: \: \: \: - \: \: \: \: \: \: - \\ ...................... \\ 2a + 0 = 4 \\ 2a = 4 \\ a = \frac{4}{2} \\ a = 2 \\ put \: a = 2 \: \: in \: a + 5b = 22 \\ 2 + 5b = 22 \\ 5b = 22 - 2 = 20 \\ b = \frac{20}{5} \\ b = 4 \\ \: so \: \: solution \: of \: (a...b) = (2...4)$

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Answer 2

Answer:

a = 2 , b = 4

Step-by-step explanation:

3a + 5b = 26 ...(1)

a + 5b = 22 ...(2)

Subtracting eq. (2) from eq.(1) , we get

3a + 5b - (a + 5b) = 26 - 22

=> 3a + 5b - a - 5b = 4

=> 2a = 4

=> a = 2

From eq.(2) , we get

a + 5b = 22

=> 2 + 5b = 22

=> 5b = 22 - 2

=> 5b = 20

=> b = 4

Hence,

a = 2

b = 4