Math, asked by mudit1013, 1 year ago

Solve this equation : 4√3x²+5x-2√3=0​

Answers

Answered by Anonymous
2

 =  >

↪4 \sqrt{3}  {x}^{2}  + 5x - 2 \sqrt{3}

↪4 \sqrt{3}  {x}^{2}  + 8x - 3x - 2 \sqrt{3}

↪4x( \sqrt{3} x + 2) -  \sqrt{3}  \\ ( \sqrt{3} x + 2) = 0

↪(4x -  \sqrt{3} )( \sqrt{3} x + 2) = 0

x =  \frac{ \sqrt{3} }{4}  \:  \: or \: x =  \frac{ - 2}{root 3}

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