solve this equation 90=n/2[2×2+(n-1)]
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90=n/2{4+n-1}
90=n/2{n+3}
90×2=n^2+3n
n^2+3n-180=0
n^2+15n-12n-180=0
;n(n+15)-12(n+15)=0
;(n+15)(n-12)=0
;n=12,-15
90=n/2{n+3}
90×2=n^2+3n
n^2+3n-180=0
n^2+15n-12n-180=0
;n(n+15)-12(n+15)=0
;(n+15)(n-12)=0
;n=12,-15
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