solve this equation by elimination method 3 x minus 4 Y = 11,
7 x minus 5 Y equal 4
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Refer the attachment for method
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Given equations :
3x - 4y = 11 .....( 1 )
7x - 5y = 4 .......( 2 )
Multiply ( 1 ) by 5 and ( 2 ) by 4, we get
5 ( 3x - 4y ) = 5 ( 11 )
→ 15x - 20y = 55
And
4 ( 7x - 5y ) = 4 ( 4 )
→ 28x - 20y = 16
Now, Subtract both the new formed equations, we get
( 15x - 20y ) - ( 28x - 20y ) = 55 - 16
15x - 20y - 28x + 20y = 55 - 16
- 13x = 39
x = - 39/13
x = - 3
Put this value in ( 1 ), we get
3 ( - 3 ) - 4y = 11
- 9 - 4y = 11
- 4y = 11 + 9
- 4y = 20
y = - 20/4
y = - 5
Hence, x = - 3, y = - 5
______Elimination Method______
In this method, the coefficients of one variable in both equations has to be same, so that it can be easily eliminate by addition or subtraction.
3x - 4y = 11 .....( 1 )
7x - 5y = 4 .......( 2 )
Multiply ( 1 ) by 5 and ( 2 ) by 4, we get
5 ( 3x - 4y ) = 5 ( 11 )
→ 15x - 20y = 55
And
4 ( 7x - 5y ) = 4 ( 4 )
→ 28x - 20y = 16
Now, Subtract both the new formed equations, we get
( 15x - 20y ) - ( 28x - 20y ) = 55 - 16
15x - 20y - 28x + 20y = 55 - 16
- 13x = 39
x = - 39/13
x = - 3
Put this value in ( 1 ), we get
3 ( - 3 ) - 4y = 11
- 9 - 4y = 11
- 4y = 11 + 9
- 4y = 20
y = - 20/4
y = - 5
Hence, x = - 3, y = - 5
______Elimination Method______
In this method, the coefficients of one variable in both equations has to be same, so that it can be easily eliminate by addition or subtraction.
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