Question

Solve this equation by using quadratic formula Or Shridharacharya's rule
$x ^{2} + 6a - (a ^{2} + 2a - 8) = 0$
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Answer 1

Answer:

-3±(a+1)

Step-by-step explanation:

Formula for roots of quadratic

expression ax 2+bx+c=0 is

=2a−b± b2−4ac

So for x2+6x−(a2+2a−8) is

= 2−6± 36+4(a 2+2a−8)

= 2−6± 9−8+a 2+2a

= 2−6 ± (a+1) 2

=−3±(a+1)