Question

solve this equation in substitution method
x+2y-4=0
2x+4y-12=0​

Answer 1

Answer:

x+2y-4=0 ---- (1) and 2x+4y-12=0 -----(2)

let, 2x+4y-12=0

x = 12-4y / 2 -----(3)

now, put the value of x in eq. (1)

[12 - 4y / 2 ] + 2y -4 = 0

6 - 4y + 2y - 4=0

2 - 2y = 0

-2y = - 2

y = 1

now put the value of y in eq. (3)

x = 12- 4y / 2

x = 12 - 4(1) / 2

x = 8 / 2

x = 4

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