Question

solve this equation: x= - 2, y=1 then find: 2x^2-3y^2+6x-2y​

Answer 1

$2 {x}^{2} - 3 {y}^{2} + 6x - 2y$

$2 { (- 2)}^{2} - 3 {(1)}^{2} + 6( - 2) - 2(1)$

$2 \times 2 \times 2 - 3 \times 1 + 6 \times - 2 - 2 \times 1$

$8 - 3 - 12 - 2$

$- 9$

u'r done!!

Thnx✌️♥️~

Answer 2

$- 9 \: is \: the \: answer$

Thnx✌️♥️~