Question

The sides of a triangle are 8 cm, 11 cm and 13 cm. What is its area(in cm square)?
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Answer 1

Answer:

8√30 cm²

Step-by-step explanation:

Given: The sides of the triangle are 8cm,11cm and 13cm.

To find: Area of the triangle

a = 8cm

b = 11cm

c = 13cm

Perimeter of the ∆ = a + b + c

→ 8 + 11 + 13

→ 32 cm

Semi-perimeter = a+b+c/2

→ 32/2 cm

→ 16cm

Area of ∆ → √s (s-a) (s-b) (s-c)

→ √ 16 (16-8) (16-11) (16-13)

→ √ 16 (8) (5) (3)

→ √ 2 ×2 ×2 ×2 ×2 ×2 × 5 × 3

→ 2 ×2 ×2 √2 × 5 × 3

→ 8√30 cm²

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