Question

solve this fast. i will mark u as the brainliest if the answer has a correct explanation: (1/cos a+sin a-1) +(1/cos a+sin a+1)=cosec a+sec a

Answer 1

Answer:

Step-by-step explanation:

Let us assume theta to be "A"

To prove:

(sinA+1+cosA)(sinA–1+cosA)(secAcosecA) = 2

Proof

LHS

(sin^2A –sinA+sinAcosA+sinA–1+cosA+cosAsinA–cosA+cos^2A)(1/sinAcosA)

sin^2A+cos^2A–1–sinA+sinA+cosA–cosA+sinAcosA+cosAsinA)(1/sinAcosA)

(1–1+2sinAcosA)(1/sinAcosA)

2sinAcosA/cosAsinA

= 2

LHS = RHS

Hence proved

Hope it helps you