Question

solve this fast.....no spams.and with Full explanation​

Answer 1

hey mate ,

Sec theta = Hypotenuse / Base = 6

Thus hypotenuse = 6 x

and base = 1x

as x is the common ratio...

Thus using PGT

AC ^2 - BC ^2 = AB^2

AB^2 = 36x^2 - x^2

AB^2 = 35x^2

AB = √[35x^2]

AB = √35 x = Perpendicular

Thus ,

Sin theta = Perpendicular / Hypotenuse

= √35x / 6x

= √35 / 6

Cos theta = 1/ Sec theta = 1/6

Tan theta = Perpendicular / Base

= √35 x / x

= √35

Cosec theta = 1/ Sin theta

= 6/√35

Cot theta = 1/tan theta

= 1/√35

Hope you find it helpful !!!!!

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