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hey mate ,
Sec theta = Hypotenuse / Base = 6
Thus hypotenuse = 6 x
and base = 1x
as x is the common ratio...
Thus using PGT
AC ^2 - BC ^2 = AB^2
AB^2 = 36x^2 - x^2
AB^2 = 35x^2
AB = √[35x^2]
AB = √35 x = Perpendicular
Thus ,
Sin theta = Perpendicular / Hypotenuse
= √35x / 6x
= √35 / 6
Cos theta = 1/ Sec theta = 1/6
Tan theta = Perpendicular / Base
= √35 x / x
= √35
Cosec theta = 1/ Sin theta
= 6/√35
Cot theta = 1/tan theta
= 1/√35
Hope you find it helpful !!!!!
Do mark it as brainliest !!!!!!!
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