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Step-by-step explanation:
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Step-by-step explanation:
➡️n(A U B) = n(A only) + n(B only) + n(A ∩ B)
➡️n(A U B) = n(A) - x + n(B) - x + x
➡️n(A U B) = n(A) + n(B) - x - x + x
➡️ n(A U B) = n(A) + n(B) - 2x + x
➡️n(A U B) = n(A) + n(B) - x
n(A U B) = n(A) + n(B) - n(A ∩ B)
Hence proved ..
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