Math, asked by smartpayal, 1 year ago

solve this ⬇️⬇️⬇️
Find the correct result.
Remember the maths is exact✔️✔️✔️
1+4=5
2+5=12
3+6=21
5+8=?
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Answers

Answered by Anonymous
57

Method 1.

→ 1 + 4 = 5

= (1×4) + 1 = 5

→ 2 + 5 = 12

= (2×5) + 2 = 10 + 2 = 12

→ 3 + 6 = 21

= (3×6) + 3 = 18 + 3 = 21

If we notice carefully the above formula is like (X × M) + X

What multipled is added again. First one multiplied with four and one is added again. Then, two multiplied with five and two is added again and so on.

Next case will be like:

[ 4 + 7 = 32

(4×7) + 4 = 28 + 4 = 32 ]

→ 5 + 8 = 45

= (5×8) + 5 = 40 + 5 = 45

•°• 5 + 8 = 45

Method 2.

First one is simple adition i.e. 1 + 4 = 5. Nothing can be added, subtracted, squared, multiplied, divide etc.

Now, let's come to the second one i.e.

2 + 5 = 12

But 2 + 5 = 7. Now, subtract 7 from 12 (12 - 7 = 5). On subtracting we get 5.

So, 2 + 5 + (5) = 12

Similarly,

3 + 6 = 21

But 3 + 6 = 9. Again, subtract 9 from 21, we get 12.

So, 3 + 6 + (12) = 21

What we get after addition, we are adding the same number in the second one and getting the result.

Therefore,

1 + 4 = 5

2 + 5 + (5) = 12

3 + 6 + (12) = 21

[ 4 + 7 + 21 = 32 ]

→ 5 + 8 + (32) = 45


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Answered by Anonymous
42

Given pattern is :-

\sf{1+4=5}

\sf{2+5=12}

\sf{3+6=21}

We have to obtain for,

\sf{5+8}

Solution :

The pattern must follow a definite sequence so as to obtain the results. Let's try and figure it out.

Let's start. Be open minded to solve such kinda question.

Let's see how do we get, 1 + 4 = 5 and if we are able to figure that out, we can thereby use the same logic and find the required answer.

\sf{1\:+(4\:\times\:1)\:=\:1\:+\:4\:=\:5}

We clearly see that, the first number is multiplied by the second number and the result obtained is sumed with the first number.

Let's see if all others too follows this pattern.

\sf{2\:+5\:=\:2\:+(5\:\times\:2)\:=\:2+10=12}

The second one is also satisfied using the same logic.

For the third one,

\sf{3+6\:=\:3+(3\times\:6)=3+18=21}

And finally, approaching to the last one and applying the same logic.

\sf{5+(8\times\:5)=5+40=45}

So, the answer to 5 + 8 is 45.

Method 2 :

Such kind of question mostly have more than one solution or logic used to solve the question.

So, let's try another method too and see whether we get the same result.

We know that 1 + 4 = 5, so that's quite simple one following the usual math.

For the second one, 2 + 5 = 12.

\sf{2+5=(5+2)+5=7+5=12}

We see, the result obtained by adding the first two number is subtracted from the LHS (12) and added to the sum of the first two number.

In the above case, we added (2 and 5) which resulted in 7, and we added the second number to obtained result. Now, hereafter, we will consider the case of previous number + 2, from the above calculation, our previous number is 7 and adding 2, we get 9 (this will be our previous number for next case) and adding the LHS of the previous equation to the next case.

For 3 + 6 = 21,

\sf{3+6=9+12=21}

From here our previous number will be 9 + 2 = 11 and LHS of previous equation is 21,

One missing case, 4 + 7,

\sf{4+7=4+7+21=11+21=32}

Here, we have LHS = 32

For 5 + 8,

\sf{5+8\:=\:5+8+32\:=\:45}

There are many other possible ways still. I have provided two possible ways.


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StarrySoul: Atiiiii Uttaaamm! xD
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