Question

solve this
find the roots of the equation 15x²-10√6x+10=0

Answer 1

hi I am not sure,
-b^2+-√b^2-4ac/2a
=-(-10√6)+-√(-10√6)^2-4.15.10/2.15
=10√6+-√600-600/30
=10√6/30
=√6/3
hopes I helped u after line you can
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Answer 2

Hi ,

15x² - 10√6 x +10= 0

Divide each term with 5, we get

3x² - 2√6 x + 2 = 0

( √3 x )² - 2 × ( √3 x ) × √2 + ( √2 )² =0

It is in the form of an identity

( a - b )² = a² -2ab + b²

( √3 x - √2 )² = 0

Therefore,

√3 x - √2 = 0 or √3 x - √2 = 0

x = √2 / √3 or x = √2 / √3

Equal roots .

I hope this helps you.

:)