Question

Solve this from the exponent chapter but no irrelevant answers​

Answer 1

Question :- 7^(1-2x) * 49³ * 343 = 1/7^(-4)

Solution :-

→ 7^(1-2x) * 49³ * 343 = 1/7^(-4)

→ 7^(1 - 2x) * (7²)³ * (7)³ = 1/7^(-4)

→ 7^(1 - 2x) * (7)⁶ * (7)³ = 1/7^(-4)

using a^m * a^n * a^p = a^(m + n + p) in LHS,

→ 7^(1 - 2x + 6 + 3) = 1/7^(-4)

using a^(-m) = 1/a^m in RHS,

→ 7^(1 - 2x + 6 + 3) = 1/{1/7⁴}

→ 7^(1 - 2x + 6 + 3) = 7⁴

finally , using a^m = a^n , then, m = n , we get,

→ (1 - 2x + 6 + 3) = 4

→ (10 - 2x) = 4

→ 2x = 10 - 4

→ 2x = 6

→ x = 3 .

Answer 2

Answer:

sorry for any mistake.......... kasa hooooo