Math, asked by Anonymous, 11 months ago

solve this full passage,​

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Answers

Answered by Anonymous
11

Answer:

Step-by-step explanation:

f(x)=

1 + 2x + 3 {x}^{2}  + 4 {x}^{3}

f'(x)=

2 +  6x +12  {x}^{2}

D=36-96

D=-60

Thus f'(x)>0

If a is a real root and y and z be other root.

So f(y).f(z)<0

Putting this with options

The option c is correct for question 8.

Question 9

t=|s|

1/2<t<3/4

Area=

t +  {t}^{2}  +  {t}^{3}  +  {t}^{4}

So the minimum value of t is 1/2 and maximum value is 3/4.

Area when t=1/2=15/16

Area when t=3/4=525/256

So option A fits it.

Option A is correct.

Question 10

Option B is correct.

&lt;marquee&gt;</p><p>Please mark as brainliest.&lt;/marquee&gt;

Answered by singlesitaarat31
8

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Question 9

t=|s|1/2<t<3/4

Area=t + {t}^{2} + {t}^{3} + {t}^{4}t+t 2 +t 3 +t 4

So the minimum value of t is 1/2 and maximum value is 3/4.

Area when t=1/2=15/16

Area when t=3/4=525/256

So option A fits it.

Option A is correct.

Question 10

Option B is correct.

PASSAGE:-

f(x)=1 + 2x + 3 {x}^{2} + 4 {x}^{3}1+2x+3x 2 +4x 3

f'(x)=2 + 6x +12 {x}^{2}2+6x+12x 2

D=36-96

D=-60

Thus f'(x)>0

If a is a real root and y and z be other root.

So f(y).f(z)<0

Putting this with options

The option c is correct for question 8.

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\blue {FOLLOW\:ME}

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