Question

solve this guys
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Answer 1

K = 2

See the attached image for detail explanation.

Thank you :)

Answer 2

Questions

• ${kx}^{2} - (k + 3)x - 3$

$\huge\sf\mathbb\color{y} \underline{\colorbox{b}{☯SoLuTiOn☯}}$

If (3) is a factor of k(x) then

• K = (3) =0

By factor theorem

Now,

On subsisting x = 3

$k(x) = k {x}^{2} - (k + 3)x - 3$=0

$k(3) = k \times {(3)}^{2} - [k + 3] 3 - 3 = 0$

$\: \: \: \: = 9k - 3k - 9 - 3 = 0$

$\: \: \: \: \: = 6k - 12 = 0$

$\: \: \: k = \frac{6}{12}$

$\: \: \: \: \: k= 2\: \: \:$