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Hii mate,
here we have two equations with exactly one common root
x^2 + ax + b = 0 and x^2 + bx + a = 0
let y be the exact common root.
therefore, y^2 + ay + b = 0 …..(1)
and y^2 + by + a = 0 ……..(2)
now subtracting eq (1) from (2) we get ,
y(a - b) + (b - a) = 0
=> y (a - b) = - (b -a)
=>y (a - b) = (a - b)
=>y = 1
Therefore the common root is 1.
Substituting value of y in equation (1)
(1)^2 + a(1) + b = 0
=>1 + a + b = 0
=>a+b+1=0
HOPE IT HELPS,
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