Question

solve this gyestion i have problem

Answer 1

Answer :

$\frac{1}{3}$

Solution :
__________

$\frac{ {3}^{40} + {3}^{39} + {3}^{38} }{ {3}^{41} + {3}^{40} + {3}^{39} } \\ \\ On \: dividing \: and \: multiplying \: by \: 3 :\\ \\ = > \frac{3( {3}^{40} + {3}^{39} + {3}^{38} ) }{3( {3}^{41} + {3}^{40} + {3}^{39}) } \\ \\ = > \frac{( {3}^{41} + {3}^{40} + {3}^{39} )}{3( {3}^{41} + {3}^{40} + {3}^{39}) } \\ \\ = > \frac{1}{3}$

So, the answer will be 1/3