Solve this
i) (✓2+✓3)+(✓3-✓2)/(✓2-✓3)+(✓3+✓2)
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Solution:
[(√2+√3)+(√3-√2)]/[(√2-√3)+(√3+√2)]
= [√2+√3+√3-√2]/[√2-√3+√3+√2]
= (2√3)/(2√2)
= (√3)/(√2)
= (√3×√2)/(√2×√2)
= √6/2
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