Tan (a+2b)=1/2,tan2(a-b)=1/3 ,find a
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Tan (a+2b)=1/2,tan2(a-b)=1/3 ,find a
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tan(a+2b)
Binaysahani:
sorry this is not complete
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Answer:
Tan3A=tan[(A+2B)+2(A-B)]
Tan3A=tan((A+2B)+tan2(A-B)/1-tan(A+2B)tan2(A-B)
Tan3A=1/2+1/3/1-1/2×1/3
Tan3A=5/6/5/6=1
Tan3A =tan45
3A=45
A=15
Tan3A
Step-by-step explanation:
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