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A being on y axis may be chosen as(0,a) .The diagonals intersect at P(1,2) .
Again we know that the diagonals will be parallel to the angle bisectors of the two sides y=x+2 and y=7x+3
i,e
5x-y+10=+-(7x-y+3)
2x+4y-7=0 and 12x-6y+13=0
=-1/2 and m
Let diagonal d be parallel to 2x+4y-7=0 and digonals D be parallel to 12x-6y+13=0 .The vertex A could be on any of the two diagonals .Hence slope of AP is either -1/2 or 2
⇒2-a/1-0=2 or -1/2
⇒a=0 or 5/2
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