Question

solve this if u feel u are gud in maths

Answer 1

First solve = √7-1/√7+1
= (√7-1)(√7-1)/(√7+1)(√7-1)
= (√7-1)²/(√7²-1²)
= √7²+1²-2(√7)(1)/(7-1)
= 7+1-2√7/6
= (8-2√7)/6
= (4-√7)/3

Now,
√7+1/√7-1
= (√7+1)(√7+1)/(√7-1)(√7+1)
= (√7+1)²/(√7²-1²)
= √7²+1²+2(√7)(1)/(7-1)
= 7+1+2√7/6
= 8+2√7/6
= (4+√7)/3

Required answer:-
= (√7-1)/(√7+1) – (√7+1)/(√7-1)
= {(4-√7)/3} – {(4+√7)/3}
= [4-√7-(4+√7)]/3
= (4-√7-4-√7)/3
= -2√7/3 = a+b√7

By comparing,we get
a = 0 and b = -2/3

Hope it helps

Answer 2

Hello friend!.
Here's ur answer!
Root7-1/Root 7+1
= (root 7-1)(root 7-1)/(root 7+1)(root 7-1)
= (root 7-1)²/(root 7²-1²)
= root 7²+1²-2(root 7)(1)/(7-1)
= 7+1-2root 7/6
= (8-2root 7)/6
= (4-root 7)/3
Root 7+1/root 7-1
= (Root 7+1)(root 7+1)/(root 7-1)(root 7+1)
= (root 7+1)²/(root7²-1²)
= root 7²+1²+2(root7)(1)/(7-1)
= 7+1+2root 7/6
= 8+2root 7/6
= (4+root 7)/3
= (root 7-1)/(root 7+1) – (root 7+1)/(root 7-1)
= {(4-root 7)/3} – {(4+root 7)/3}
= [4-root 7-(4+root 7)]/3
= (4-root 7-4-root 7)/3
= -2root 7/3 = a+ b root7
comparing,
a = 0and b = -2/3