Question

Solve this if you can:

ABC is right angled triangle, angle B=90 degree, D is the midpoint of AC, AB=3cm, BC=4cm, measure of BD will be
(a) 5cm
(b) 7cm
(c) 2.5cm
(d) 2 cm

Answer 1

Given, D is midpoint of AC.

By Pythagorean theorum,

AB^2+BC^2=AC^2

By substituting the values,

AC=5

Then AD will be 2.5cm.

Now in triangle ABD,

AB^2=BD^2+AD^2

By solving it, we will get,

1.65=BD

Answer 2

In ABC, angle b=90 ,AB=3,BC=4

By P. T,

AB²+BC²=AC²

3²+4²=AC²

9+16=AC²

AC=5

NOW,

BY PROPERTY OF HYPOTENUSE AND MEDIAN,

BD=1/2×AC

=1/2×5

=2.5

BD=2.5