Question

solve this in a easy. method so that i can understand properly

Answer 1

Hi...☺️

Here is your answer...✌️

$\frac{16 \times {2}^{n + 1 } - 4 \times {2}^{n} }{16 \times {2}^{n + 2} - 2 \times {2}^{n + 2} } \\ \\ =\frac{8 \times (2^1 \times {2}^{n + 1}) - ({2}^{2} \times {2}^{n}) }{ {2}^{n + 2} (16- 2 )} \\ \\ = \frac{8 \times {2}^{n + 2 } - {2}^{n + 2} } { {2}^{n + 2} \times 14} \\ \\ = \frac{ {2}^{n + 2}(8 - 1) }{ {2}^{n + 2} \times 14} \\ \\ = \frac{7}{14} \\ \\ = \frac{1}{2}$

Answer 2

Your answer is 1/2
....