Math, asked by bhakunisaksham390, 2 months ago

solve this in a rough or a bar graph notebook plz

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Answered by doremondisny
1

Answer:

The sales in:

The sales in:(i) 2002 was Rs.4 crores and (ii) 2006 was Rs.8 crores

The sales in:(i) 2002 was Rs.4 crores and (ii) 2006 was Rs.8 crores(b) The sales in:

The sales in:(i) 2002 was Rs.4 crores and (ii) 2006 was Rs.8 crores(b) The sales in:(i) 2003 was Rs.7 crores and (ii) 2005 was Rs.10 crores.

The sales in:(i) 2002 was Rs.4 crores and (ii) 2006 was Rs.8 crores(b) The sales in:(i) 2003 was Rs.7 crores and (ii) 2005 was Rs.10 crores.(c) The difference of sales in 2002 and 2006 = Rs.8 crores–Rs.4 crores= Rs.4 crores

The sales in:(i) 2002 was Rs.4 crores and (ii) 2006 was Rs.8 crores(b) The sales in:(i) 2003 was Rs.7 crores and (ii) 2005 was Rs.10 crores.(c) The difference of sales in 2002 and 2006 = Rs.8 crores–Rs.4 crores= Rs.4 crores(d)In the year 2005, there was the greatest difference between the sales and compared to its previous year, which is (Rs. 10crores –Rs. 6crores) = Rs. 4crores.

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