Math, asked by Anonymous, 11 months ago

Solve this in copy and attach it .

Attachments:

Anonymous: ??
Anonymous: set 1 was difficult maine suna
Anonymous: was it?
Anonymous: YEH NCERT MEI SOLVED EXAMPLE HAI
Anonymous: Haa behen bahut difficult tha
Anonymous: mera sahi tha

Answers

Answered by Anonymous
4

Answer:

Let P be the pole to be erected and A, B be the opposite fixed gates.

Given, PA – PB = 7

Let PA = a, PB = b

Hence a – b = 7

⇒ a = 7 + b �...(1)

In right ΔPAB,

AB2 = AP2 + BP2 (By Pythagoras theorem)

132 = a2 + b2

169 = (7 + b)2 + b2

169 = 49 + 14b + 2b2

2b2 + 14b – 120 = 0

b2 + 7b – 60 = 0

b2 + 12b - 5b – 60 = 0

b(b + 12) - 5(b + 12) = 0

(b + 12)(b – 5) = 0

Hence b = 5 or – 12

But ‘b’ cannot be negative

Therefore, b = 5

⇒ a = 7 + 5 = 12

Hence, PA = 12 m and PB = 5 m

thanks

Attachments:

Anonymous: attach figure too
Anonymous: okay
Anonymous: mark me brainliest
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