solve this in method .....
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1
here,
n/2 = 140
cf= 49
f=133
h=5
l=10
median=l+(n/2-cf/f)*h
=10+(140-49/133)5
=10+(91/133)5
=10+455/133
=1330+455/133
=1785/133
=13.42
n/2 = 140
cf= 49
f=133
h=5
l=10
median=l+(n/2-cf/f)*h
=10+(140-49/133)5
=10+(91/133)5
=10+455/133
=1330+455/133
=1785/133
=13.42
Answered by
2
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