Solve this Math sum...
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The odd integers from 1 to 2001 are 1, 3, 5, …1999, 2001.
This sequence forms an A.P.
Here, first term, a = 1 Common difference, d = 2
Here, a+(n−1)d=2001 =>1+(n−1)(2)=2001 =>2n−2=2000 =>n=1001 Sn=n2[2a+(n−1)d] ∴Sn=10012[2×1+(1001−1)×2] =10012[2+1000×2] =10012×2002 =1001×1001 =1002001
Thus, the sum of odd numbers from 1 to 2001 is 1002001.
Hope this helps!
The odd integers from 1 to 2001 are 1, 3, 5, …1999, 2001.
This sequence forms an A.P.
Here, first term, a = 1 Common difference, d = 2
Here, a+(n−1)d=2001 =>1+(n−1)(2)=2001 =>2n−2=2000 =>n=1001 Sn=n2[2a+(n−1)d] ∴Sn=10012[2×1+(1001−1)×2] =10012[2+1000×2] =10012×2002 =1001×1001 =1002001
Thus, the sum of odd numbers from 1 to 2001 is 1002001.
Hope this helps!
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