Question

Solve this maths question of class X ICSE
$\frac{2x}{x-4}$ + $\frac{2x-5}{x-3}$ =$\frac{25}{3}$

Answer 1

$Given:\frac{2x}{x - 4}+\frac{2x - 5}{x - 3}=\frac{25}{3}$

$LCM = 3(x - 4)(x - 3)$

$=>\frac{2x}{x - 4}*3(x - 4)(x - 3)+\frac{2x -  5}{x - 3}*3(x - 4)(x - 3)=\frac{25}{3} * 3(x - 4)(x - 3)$

$=>6x(x - 3)+3(2x - 5)(x - 4)=25(x - 4)(x - 3)$

$=> 6x^2 - 18x + 6x^2 - 39x + 60 = 25x^2 - 175x + 300$

$=>12x^2 - 57x + 60 = 25x^2 - 175x + 300$

$=>12x^2 - 57x + 60 - 25x^2 + 175x - 300 = 0$

$=>-13x^2 + 118x - 240=0$

$=> 13x^2 - 118x + 240=0$

$=> 13x^2 - 40x - 78x + 240=0$

$=> x(13x - 40) - 6(13x - 40)=0$

$=> (x - 6)(13x - 40)=0$

$=>\boxed{x = 6,\frac{40}{13}}$

Hope it helps!

Answer 2

Answer:

imposible tor me

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