Question

the sum of the digits of two digits no is 13.the no obtained by interchanging tge digits of the given no exceed that no by 27 find the no

Answer 1

So....
Given
x + y = 13
10x+ y+27 = 10y+ x

From eq q
x= 13-y
so
10(13-y) +y + 27 = 10y + 13 -y
130- 10y + y +27 = 10y + 13 - y
157 - 9y = 9y + 13
18y = 170
y = 170/ 18=9.4

now substitute it in eq 1
x + 9.4 =13
x = 13-9.4= 3.6

So y = 9.4 and x = 3.6

Answer 2

Answer:

Step-by-step explanation:

Let x be the teens place no.&y be the ones place no.

Asp cond-I

x+y=13-----(1)

Asp cond -II

10y+x=10x+y+27

9y-9x=27

y-x=3

x-y=-3----(2)

(1)+(2)

x+y=13

x-y=-3

-----------

2x=10

x=5

x+y=13

5+y=13

y=8

Therefore the no.

= 10x+y

=10*5+8

= 50+8

=58