Solve this .. Not getting.
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Answered by
4
Answer:
Kindly refer to the attachment for your answer!!
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Thanks for the question :)
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vanshika1338:
thanks alot dear ☺️
Answered by
3
Answer:
hey mate here is your answer...
a+b+c=6
ab+bc+ca=11
(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)
(6)^2-22=a^2+b^2+c^2
36-22=a^2+b^2+c^2
14=a^2+b^2+c^2
a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)
=6(14-(ab+bc+ca)
=6(14-11)
=6×3
=13
so, a^3+b^3+c^3-3abc=18
hope it may help u..
and thanks for this wonderful question
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