Math, asked by vanshika1338, 11 months ago

Solve this .. Not getting. ​

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Answers

Answered by LovelyG
4

Answer:

Kindly refer to the attachment for your answer!!

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Answered by samrudhi15
3

Answer:

hey mate here is your answer...

a+b+c=6

ab+bc+ca=11

(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)

(6)^2-22=a^2+b^2+c^2

36-22=a^2+b^2+c^2

14=a^2+b^2+c^2

a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)

=6(14-(ab+bc+ca)

=6(14-11)

=6×3

=13

so, a^3+b^3+c^3-3abc=18

hope it may help u..

and thanks for this wonderful question


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