solve this numerical
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Let h1 and h2 be the max. height attained by stones.
For first stone max. Height that is h1 will be equal to u1 square/2g
For second stone max. Height that is h2 will be equal to u2 square/2g.
h1/h2 = u1 square / u2 square
Hope you get your answer.
For first stone max. Height that is h1 will be equal to u1 square/2g
For second stone max. Height that is h2 will be equal to u2 square/2g.
h1/h2 = u1 square / u2 square
Hope you get your answer.
Rahul1720:
i think i want some more explanation for this
Answered by
1
Use equation of motion
S = (v² - u²)/(2a)
Stone is thrown upwards. Direction of velocity is opposite to the direction of acceleration due to gravity. So take a = -g
You’ll get H₁ : H₂ = u₁² : u₂²
For detailed solution refer to the image attached.
S = (v² - u²)/(2a)
Stone is thrown upwards. Direction of velocity is opposite to the direction of acceleration due to gravity. So take a = -g
You’ll get H₁ : H₂ = u₁² : u₂²
For detailed solution refer to the image attached.
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