Math, asked by rajeshkumarsinghb, 7 months ago

solve this on the basis of simultanious linear equation:4x-3y=xy
1/x+2/y=3

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Answers

Answered by daraboinaraju4
1

Answer:

Step-by-step explanation:

3x+2y=7

4x+y=6⇒y=6−4x

placing in equation (1)

3x+2(6−4x)=7

3x+12−8x=7⇒−5x+12=7

−5x=7−12⇒−5x=−5

x=1

∴ y = 6 - 4×1=2

∴ x = 1, y = 2

Answered by ScienceMathsLover
1

4x - 3y = xy

4x = xy + 3y

 x = \frac{xy + 3y}{4}

As we can see x on both sides so we can cancel them:

1 =  \frac{y + 3y}{4}

4 = 4y

y = 1

We now have the value of y. So:

 \frac{1}{x}  +  \frac{2}{y}  = 3

 \frac{1}{x}  +  \frac{2}{1}  = 3

 \frac{1}{x}  = 3 - 2

 \frac{1}{x}  = 1

x = 1

We now got the values of x=y=1

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