Question

Solve this one Correctly and I will mark you as brainliest​

Answer 1

To prove that the perpendicular from the centre to a chord bisect the chord.

Consider a circle with centre at O and AB is a chord such that OX perpendicular to AB

To prove that   AX=BX

In ΔOAX and ΔOBX

∠OXA=∠OXB  [both are 90 ]

OA=OB  (Both  are radius of circle )

OX=OX  (common side )

ΔOAX≅ΔOBX

AX=BX  (by property of congruent triangles )

hence proved.