Solve this one pleaseeeeeeeeee
I will make you a brainliest
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Answer:
Proving
Step-by-step explanation:
let theta =x
Lets see it as (sinx - 2cos^3x/(2cos^3x - Cosx) = tanx
so sin x - 2sin3x /
2cos3x - cosx = tanx
= sinx(1 - 2sin2x) /
cosx(2cos2x - 1)
=sinx[1 -2(1 -cos2x)]
/
cosx(2cos2x - 1)
=sinx[1 - 2 + 2cos2x]
/
cosx(2cos2x - 1)
=sinx[2cos2x - 1]
/
cosx(2cos2x - 1)
= sinx
cosx
= tanx = rhs
Hope it helps..........
Don't forget to mark me as brainliest!!!!!!!!!!!!!!!!!!!!!!!!!
hemangipandya456:
Hey...you told to mark me as brainliest!!!
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